1.输入任意 4 个字符(如：abcd)，并按反序输出(如：dcba)。
C++
#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
/* int main()
{
string s;
cin>>s;
reverse(s.begin(),s.end());
cout<<s<<endl;
return 0;
}*/
int main()
{
string s;
cin>>s;
for(int i=s.size()-1;i>=0;i--)
{
cout<<s[i];
}
cout<<endl;
}
Golang
package exam2000
import (
"fmt"
)
//Reverse is used to reverse a string.
func Reverse() {
var s1 string
fmt.Scan(&s1) //Scan接收字符型变量时只接收整型,即ASCII码
for i := len(s1) - 1; i >= 0; i-- {
fmt.Printf("%c", s1[i])
}
}
2.设 a、b、c 均是 0 到 9 之间的数字，abc、bcc 是两个三位数，且有：abc+bcc=532。求满足条件的所有 a、b、c 的值。
C++
#include <iostream>
using namespace std;
int main()
{
int a,b, c;
int x,y;
for(a=0;a<10;a++)
for(b=0;b<10;b++)
for(c=0;c<10;c++)
{
x=a*100+b*10+c;
y=b*100+c*10+c;
if(x+y==532)
{
cout<<a<<' '<<b<<' '<<c<<endl;
}
}
return 0;
}
Golng
package exam2000
import "fmt"
// Abc is used to find a special number.
func Abc() {
var a, b, c int
var x, y int
for a = 0; a < 10; a++ {
for b = 0; b < 10; b++ {
for c = 0; c < 10; c++ {
x = a*100 + b*10 + c
y = b*100 + c*10 + c
if x+y == 532 {
fmt.Println(a, b, c)
}
}
}
}
}
3.一个数如果恰好等于它的各因子（该数本身除外）子和，如： 6=3+2+1，则称其为“完数”；若因子之和大于该数，则称其为“盈数”。求出 2 到 60 之间所有“完数”和“盈数”，并以如下形式输出： E: e1 e2 e3 ……(ei 为完数) G: g1 g2 g3 ……(gi 为盈数) 。
C++
#include <iostream>
using namespace std;
int main()
{
int a[61]={0};
for(int i=2;i<=60;i++)
{
int t=i;
for(int j=i-1;j>0;j--)
{
if(i%j==0)
{
t-=j;
}
}
if(t==0)
{
a[i]=1;
}
if(t<0)
{
a[i]=2;
}
}
cout<<"E:";
for(int i=2;i<61;i++)
{
if(a[i]==1)
cout<<i<<" ";
}
cout<<endl;
cout<<"G:";
for(int i=2;i<61;i++)
{
if(a[i]==2)
cout<<i<<" ";
}
cout<<endl;
return 0;
}
Golang
package exam2000
import "fmt"
//Eg is used to find "完数" and "溢数" between 2 and 60.
func Eg() {
var a [61]int
var i, j, t int
for i = 2; i <= 60; i++ {
t = i
for j = i - 1; j > 0; j-- {
if i%j == 0 {
t -= j
}
}
if t == 0 {
a[i] = 1
}
if t < 0 {
a[i] = 2
}
}
fmt.Print("E:")
for i = 2; i < 61; i++ {
if a[i] == 1 {
fmt.Printf("%d ", i)
}
}
fmt.Println()
fmt.Print("G:")
for i = 2; i < 61; i++ {
if a[i] == 2 {
fmt.Printf("%d ", i)
}
}
fmt.Println()
}
4.从键盘输入 4 个学生的数据( 包括姓名、年龄和成绩)，并存放在文件 sf1 上。从该文件读出这些数据，按成绩从高到底排序，并输出其中成绩次高者的所有数据。
C++
#include <iostream>
#include <fstream>
#include <algorithm>
using namespace std;
struct student
{
string name;
int age;
int score;
};
bool cmp(student a,student b)
{
return a.score>b.score;
}
int main()
{
student s;
student stu[4];
ofstream outfile;
cout<<"input students' name,age,score (Ending with 00 00 00):"<<endl;
outfile.open("sf1.txt");
while(cin>>s.name>>s.age>>s.score)
{
if(s.name=="00")
break;
outfile<<s.name<<" "<<s.age<<" "<<s.score<<endl;
}
ifstream infile;
infile.open("sf1.txt");
for(int i=0;i<4;i++)
{
infile>>stu[i].name>>stu[i].age>>stu[i].score;
}
//you can sort by yourself or use sort() included in algorithm
/* for(int i=1;i<=3;i++)
{
for(int j=0;j<4-i;j++)
{
if(stu[j].score<stu[j+1].score)
{
s=stu[j];
stu[j]=stu[j+1];
stu[j+1]=s;
}
}
} */
sort(stu,stu+4,cmp);
for(int i=0;i<4;i++)
{
cout<<stu[i].name<<" "<<stu[i].age<<" "<<stu[i].score<<endl;
}
cout<<"Next on the list is: "<<stu[1].name<<" "<<stu[1].age<<" "<<stu[1].score<<endl;
outfile.close();
return 0;
}
Golang
package exam2000
import (
"bufio"
"fmt"
"io/ioutil"
"os"
"strconv"
"strings"
)
type students struct {
name string
age int
score int
}
//Info is used to process students' data
func Info() {
//数据写入文件
var s string
var stu [4]students
filepath := "D:/sf1.txt"
file, err := os.OpenFile(filepath, os.O_WRONLY|os.O_CREATE|os.O_RDONLY, 0666)
if err != nil {
fmt.Println("文件创建打开失败", err)
}
defer file.Close() //defer 后面的语句在最后 return 之前执行
write := bufio.NewWriter(file)
fmt.Println("input the info :MM_22_99")
for i := 0; i < 4; i++ {
fmt.Scanln(&s)
write.WriteString(s)
write.WriteString("\n")
}
write.Flush()
//从文件读取数据
f, err := ioutil.ReadFile(filepath)
if err != nil {
fmt.Println("read fail", err)
}
//切割字符串，并赋值到相应的变量中
strArr := strings.Split(string(f), "\n")
for i := 0; i < 4; i++ {
y := strings.Split(string(strArr[i]), "_")
stu[i].name = y[0]
stu[i].age, err = strconv.Atoi(y[1])
stu[i].score, err = strconv.Atoi(y[2])
}
//排序
for i := 1; i < 4; i++ {
for j := 0; j < 4-i; j++ {
if stu[j].score < stu[j+1].score {
stu[j], stu[j+1] = stu[j+1], stu[j]
}
}
}
//输出排序后结果
for i := 0; i < 4; i++ {
fmt.Printf("%s %d %d\n", stu[i].name, stu[i].age, stu[i].score)
}
fmt.Printf("Next to the list is:%s %d %d\n", stu[1].name, stu[1].age, stu[1].score)
}